SteamyTea Posted December 5, 2017 Posted December 5, 2017 Bugger, missed that. Give me another so that I can keep my average at 100% wrong
Construction Channel Posted December 9, 2017 Posted December 9, 2017 I get this kind of thing on FB all the time. So I may as well let you all join in (note it is actually Saturday night @Tennentslager )
pdf27 Posted December 9, 2017 Posted December 9, 2017 I think it's 042 as well. Nothing is correct in 738, one is correct but wrongly placed in 780 - therefore the first or second digit is zero. 206 has two digits correct but wrongly placed. We already know that the first or second digit is zero, so the first digit must be zero. One of 2 or 6 makes up one of the remaining digits, with the other not being present. 682 has one digit correct and correctly placed. Since the first digit must be a zero, the correct digit must be a 2 as the third digit. 614 has one digit correct but wrongly placed. The missing digit must be a 6 or a 4, and we know from (2) that there is no 6 present. 1
Construction Channel Posted December 9, 2017 Posted December 9, 2017 12 minutes ago, JSHarris said: 602 Can’t be because in the first set only one is correct.
Tennentslager Posted December 9, 2017 Author Posted December 9, 2017 (edited) 062 Sherlock and I'm gassed ??? Edited December 9, 2017 by Tennentslager
Construction Channel Posted December 9, 2017 Posted December 9, 2017 2 minutes ago, Tennentslager said: 062 Sherlock and I'm gassed ??? as above, only one is correct in the first set
oldkettle Posted December 9, 2017 Posted December 9, 2017 (edited) 012 Edit: Oops, definitely not Edit 2. Which leaves me with 042 as above Edited December 9, 2017 by oldkettle
Tennentslager Posted April 7, 2018 Author Posted April 7, 2018 Now Buildhubbers...look carefully and remember BODMAS. Clue...it's single whole natural number or something ?????????
ProDave Posted April 7, 2018 Posted April 7, 2018 23 minutes ago, Tennentslager said: Naw Got it. A bit sneaky 3 pairs of shoes = 30, so one pair of shoes =10 1 pair of shoes plus 2 men = 20. We know pair of shoes = 10 so 2 men = 10 so 1 man = 5 man (5) plus 2 (pairs of) whistles = 13 so 2 (pairs of) whistles = 8 therefore 1 (pair of) whistles = 4 So the final sum single shoe (5) plus man (5) plus single whistle (2) = 12
Tennentslager Posted April 7, 2018 Author Posted April 7, 2018 (edited) 39 minutes ago, ProDave said: Got it. A bit sneaky 3 pairs of shoes = 30, so one pair of shoes =10 1 pair of shoes plus 2 men = 20. We know pair of shoes = 10 so 2 men = 10 so 1 man = 5 man (5) plus 2 (pairs of) whistles = 13 so 2 (pairs of) whistles = 8 therefore 1 (pair of) whistles = 4 So the final sum single shoe (5) plus man (5) plus single whistle (2) = 12 Nope there's a X in the last line...but still wrong Edited April 7, 2018 by Tennentslager
ProDave Posted April 7, 2018 Posted April 7, 2018 It's a bit more complicated. The first ones are man plus whistle and the last one is man (no whistle) Which means my values for man and whistle are wrong, and becomes a simultaneous equation to solve to get those.
Tom Posted April 7, 2018 Posted April 7, 2018 Lol, didn't realise there was another two pages to this thread... 1
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