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Calculating for the use of sand for a thermal store.


Marvin

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Is this right?

 

Dry sand density between 1520-1680 kg/m3 (say 1500 in the calculation below)

Course sand, dry, specific heat capacity is about 800 Joules per kg per degree of temperature change.

Course sand, dry, thermal conductivity 0.25 W/m K

1kWh equals 3,600,000 joules

 

And therefore, ignoring all factoring of energy loss due to energy conversion etc(what I call "in theory"):

 

Heating up 1kg of dry course sand would be:

 

450 degrees temperature change times 800 specific heat capacity times 1kg in weight, divided by the amount of joules in one kWh:

 

450 x 800 x 1000 / 3,600,000 = 1 kWh.

 

 

 

 

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13 minutes ago, Marvin said:

450 degrees temperature change times 800 specific heat capacity times 1kg in weight, divided by the amount of joules in one kWh

1 kWh.

How are you going to insulate at those temperatures?

How are you going to get the energy back out?

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Hi @SteamyTea

 

It's good to have someone capable to review my workings. I double checked because I thought you might.

 

 

15 minutes ago, SteamyTea said:

1. How are you going to insulate at those temperatures?

2. How are you going to get the energy back out?

Present theory:

 

1. From centre of store to outside: Sand, steel container, mineral wool, external weather protection.

2. Electric energy, to heat air, to heat sand. Heated sand to heated air to building. 

 

Storage capacity, thermal loss over time and building requirement are the next hurdles...

 

 

 

 

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A very interesting project. 

 

How much space do you have to play with and how much excess energy do you have to use? Is this a budgeted project with a payback window or a fun experiment?.

 

In commercial systems they're claiming about 50% round trip efficiency and storage temps of up to 500 deg C.  

 

 

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36 minutes ago, SteamyTea said:

You could compress air, which will warm up with entropy and then add in extra energy with an element.

Then release it back.

Hmm.

 

What volume of air would you need to produce the potential of 1kWh of heat?

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33 minutes ago, JohnMo said:

For extracting heat, you could use an air to water heat exchanger, such as a car intercooler to allow hot air to exchange to hot water and then feed into house.

Could add the warm air to the MVHR inlet. 

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22 minutes ago, SteamyTea said:

Aerogel is 0.013 W/m.K 

Aerogel is good but expensive with a 650C melting point (being made from the same sort of thing as sand (silica)?

 

What is it? about £10 a square foot 10mm thick? Comparative thickness of mineral wool 40mm?  this might blow the budget...

 

 

 

 

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19 minutes ago, Marvin said:

What volume of air would you need to produce the potential of 1kWh of heat?

Depends on the pressure.

The SHC is better than sand at 1kJ/kg.K.

A m³ at sea level has a density of about 1.2 kg/m².

Double the pressure, halve the volume.

 

Edited by SteamyTea
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27 minutes ago, Temp said:

Use Helium

Would need to be careful you did make a bomb, not sure of the expansion rate, but a temp rise of 450 degs, could give a big pressure rise in a contained volume of gas.

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2 minutes ago, Nickfromwales said:

Apples for apples

Not sure apples would be that good. But they don't say the fill material, but mentions solid.

 

Looked at the datasheet stores 100kWh, it states the temp drop of 500 to 200 degs takes 19 days.  The average heat loss being 5kWh day! Pretty huge losses.  Vacuum insulated.

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image.thumb.png.9f1ea440f6a13deb3b36c247a61fd5e6.png

 

I'd start with something like this. 

Then line the inside with foam boards with all joints crossed and foamed. 

Then something like dense mineral wool like that which is used for EWI that would happily take hundreds of degrees of heat. 

 

Next part is tricky, Maybe a thin steel liner, tech screwed together. 

Electric heating elements embedded in the sand then. 

Run a copper coil through it back to the house to small radiator and pump to extract the heat. 

 

300mm of PIR plus 100mm mineral wool should give a U value of about 0.06w/m2K. 

 

Assuming the volume remaining inside is about 1.8mx1.8mx3.6m you would have an internal surface area of about 32m2 and a volume of 11.7m3. Sand with a specific heat capacity of sand at 800j/kg/K and a specific density of 1.6 would give about 1.5 Mj of storage per degree or 0.4KWh/K. 

 

If you were to assume the lowest useable temp to be 40 deg and you wanted to raise temp to 100 deg it would take 24kWh of input. Not undoable. 

 

The losses however ( assuming an average temp inside of 70 deg and 10 out side would be 32m2 x 0.06 W/m2k x 60 DeltaT would be 115w or 2.76kWh per day, say 3kWh with pipe losses. 

 

 

Assuming this system was charged and discharged over a 2 day period it sounds like 24kWh in and 18kWh out = 75% Efficiency. Not nearly as bad as I expected. 

 

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