sharpener Posted December 13, 2023 Share Posted December 13, 2023 I seem to have heard somewhere that with the Vaillant figures the yield does not include the input power so you need to divide it by the input power and then add 1 to get the CoP. Don't know if this is true or not. Link to comment Share on other sites More sharing options...
Blooda Posted December 13, 2023 Share Posted December 13, 2023 9 hours ago, SuperJohnG said: The Vaillant Arotherm unit doesn't give you the COP? it only provides info on energy yield as a total, then it gives power consumption for heating and DHW, but you can only figure out an overall COP not individual. My COP was 2.74 last month. 1386kWh yield, 505 kWh power consumed. Seems like the COP isn't great. The WC I haven't messed with (largely as I don't know how) but it's fairly simple with no buffer, ASHP straight to the UFH which is a single zone. The Cop [In Vaillant terms] for this would be --- (Yield+Consumed)/Consumed --- (1386+505)/505 = 3.74, which is not bad. I 1 Link to comment Share on other sites More sharing options...
JohnMo Posted December 13, 2023 Share Posted December 13, 2023 5 minutes ago, Blooda said: The Cop [In Vaillant terms] for this would be --- (Yield+Consumed)/Consumed --- (1386+505)/505 = 3.74, which is not bad. I So the yield is just the figure for what the heat pump is gaining and not the total, for energy given out. So a CoP of one, would be a yield of zero? Link to comment Share on other sites More sharing options...
Beelbeebub Posted December 13, 2023 Share Posted December 13, 2023 8 minutes ago, Blooda said: The Cop [In Vaillant terms] for this would be --- (Yield+Consumed)/Consumed --- (1386+505)/505 = 3.74, which is not bad. I Or simply cop=yield+1 Link to comment Share on other sites More sharing options...
Beelbeebub Posted December 13, 2023 Share Posted December 13, 2023 1 minute ago, JohnMo said: So the yield is just the figure for what the heat pump is gaining and not the total, for energy given out. So a CoP of one, would be a yield of zero? I think so. My guess is that vailant are a boiler company so that thinking is sort of built in to how they view things, and the (electrical) energy consumed by a boiler is not really relevant to the final heat output. Link to comment Share on other sites More sharing options...
Blooda Posted December 13, 2023 Share Posted December 13, 2023 2 hours ago, Beelbeebub said: Or simply cop=yield+1 CoP = [Yield/consumed] + 1 1 Link to comment Share on other sites More sharing options...
Beelbeebub Posted December 13, 2023 Share Posted December 13, 2023 2 hours ago, Blooda said: CoP = [Yield/consumed] + 1 Yes, too early in the morning! Link to comment Share on other sites More sharing options...
SuperJohnG Posted December 13, 2023 Share Posted December 13, 2023 14 hours ago, Blooda said: The Cop [In Vaillant terms] for this would be --- (Yield+Consumed)/Consumed --- (1386+505)/505 = 3.74, which is not bad. I Thanks for this...seems better at that. However that's a funny way they do it! Link to comment Share on other sites More sharing options...
SuperJohnG Posted December 13, 2023 Share Posted December 13, 2023 Very helpful link for those with Arotherm units who want to understand COP figures https://energy-stats.uk/how-to-measure-vaillant-arotherm-cop/amp/ Link to comment Share on other sites More sharing options...
eandg Posted December 15, 2023 Share Posted December 15, 2023 So using that metric our COP is 3.16 which doesn't seem great. Will that improve in the better weather when the temperature differential is less? Anything we can do to improve it? Link to comment Share on other sites More sharing options...
JohnMo Posted December 15, 2023 Share Posted December 15, 2023 21 minutes ago, eandg said: So using that metric our COP is 3.16 which doesn't seem great. Will that improve in the better weather when the temperature differential is less? Anything we can do to improve it? How do you operate at the moment? Link to comment Share on other sites More sharing options...
eandg Posted December 16, 2023 Share Posted December 16, 2023 20 hours ago, JohnMo said: How do you operate at the moment? We've just left it as the installer set up. 7kW system, 50° water temperature. UFH on ground floor only set at 21°. Link to comment Share on other sites More sharing options...
JohnMo Posted December 16, 2023 Share Posted December 16, 2023 37 minutes ago, eandg said: 50° water temperature. That's why you CoP isn't great, you need to start to reduce that flow temperature, ideally set up weather compensation. Start by dropping the flow temp a couple of degrees leave for 24 hours and note down what if any has changed and outside average temp, keep doing this until the house temp drops a and doesn't recover back to 21, then add a degree back on. Your flow temp will be more likely be in the mid 30s than 50. 1 Link to comment Share on other sites More sharing options...
eandg Posted December 16, 2023 Share Posted December 16, 2023 6 hours ago, JohnMo said: That's why you CoP isn't great, you need to start to reduce that flow temperature, ideally set up weather compensation. Start by dropping the flow temp a couple of degrees leave for 24 hours and note down what if any has changed and outside average temp, keep doing this until the house temp drops a and doesn't recover back to 21, then add a degree back on. Your flow temp will be more likely be in the mid 30s than 50. Thanks - will do. Link to comment Share on other sites More sharing options...
SuperJohnG Posted December 17, 2023 Share Posted December 17, 2023 On 16/12/2023 at 07:50, eandg said: We've just left it as the installer set up. 7kW system, 50° water temperature. UFH on ground floor only set at 21°. Is that 50 degrees your DHW or UFH? I've got 52 degrees for DHW and UFH is on weather comp Link to comment Share on other sites More sharing options...
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