NotJustin Posted November 3, 2020 Share Posted November 3, 2020 Hi, I had to start this thread again with a new subject. I now have an inverter and the suppliers tell me that I wire the incoming mains DIRECTLY into it, and then to the distrubution board. So as the solar and battery drop away the mains takes over again. I will get an electrician to do this part, but I just want to make sure that this is correct? ie Mains into inverter to distruibution board? I have found this diagram and this is the inverter: https://www.photonicuniverse.com/en/catalog/full/449-Iconica-5000W-48V-hybrid-pure-sine-wave-inverter-with-4000W-solar-input-80A-500V-MPPT-solar-controller-60A-mains-battery-charger-and-inbuilt-Bluetooth-No-battery-required.html Link to comment Share on other sites More sharing options...
PeterW Posted November 3, 2020 Share Posted November 3, 2020 I’d just read pages 5-7 of the manual ... https://www.photonicuniverse.com/upload/file/Manuals/Iconica/IC3-BM/IC3-BM_user_manual.pdf Link to comment Share on other sites More sharing options...
Declan52 Posted November 3, 2020 Share Posted November 3, 2020 Put the kettle on and let an electrician do it. Link to comment Share on other sites More sharing options...
NotJustin Posted November 3, 2020 Author Share Posted November 3, 2020 The manual only refers to the wires in and out. Not how it fits into the house wiring. The electricians around here and wire up a socket but they'll have no idea about an inverter. Link to comment Share on other sites More sharing options...
NotJustin Posted November 3, 2020 Author Share Posted November 3, 2020 25 minutes ago, PeterW said: I’d just read pages 5-7 of the manual ... https://www.photonicuniverse.com/upload/file/Manuals/Iconica/IC3-BM/IC3-BM_user_manual.pdf The manual only refers to the wires in and out. Not how it fits into the house wiring. Link to comment Share on other sites More sharing options...
NotJustin Posted November 3, 2020 Author Share Posted November 3, 2020 4 minutes ago, Declan52 said: Put the kettle on and let an electrician do it. The electricians around here and wire up a socket but they'll have no idea about an inverter. Link to comment Share on other sites More sharing options...
PeterW Posted November 3, 2020 Share Posted November 3, 2020 5 minutes ago, NotJustin said: The manual only refers to the wires in and out. Not how it fits into the house wiring. Ok so this is top of page 7 - and I’ve only skim read the few pages CAUTION!! Before connecting to AC input power source, please install a separate AC breaker between inverter and AC input power source. This will ensure the inverter can be securely disconnected during maintenance and fully protected from over current of AC input. The recommended spec of AC breaker is 16A for 1.5KW and 32A for 3KW and 50A for 5KW. CAUTION!! There are two terminal blocks with “IN” and “OUT” markings. Please do NOT mis-connect input and output connectors. WARNING! All wiring must be performed by a qualified personnel. So you need to install a breaker between the inverter and the supply. Not rocket science. But the last point is key - if you’re asking those sorts of questions, you’re not qualified to install this. Electricity doesn’t have a smell, or make your socks wet when you get it wrong, it just kills - instantly. And you’re talking about wiring where then only thing between you and the grid is a 100A supply fuse that will blow long after you’ve become a crisp. Link to comment Share on other sites More sharing options...
NotJustin Posted November 3, 2020 Author Share Posted November 3, 2020 (edited) In my post I state I will get an electrician to do it, bu tI will have to advise him. Seriously, I'm not a child. Edited November 3, 2020 by NotJustin Link to comment Share on other sites More sharing options...
PeterW Posted November 3, 2020 Share Posted November 3, 2020 Sorry but get the electrician to read the manual - if they screw up then it’s on them and if they don’t know then they ask the supplier. If you advise wrongly and they blow up your £800 inverter then you have no-one to come back on but yourself. Link to comment Share on other sites More sharing options...
ProDave Posted November 3, 2020 Share Posted November 3, 2020 Oh my, there are so many things wrong with that circuit diagram I don't know where to start. This is NOT a DIY job and one for an electrician, an electrician that understands inverters and can read the manual Link to comment Share on other sites More sharing options...
SteamyTea Posted November 3, 2020 Share Posted November 3, 2020 I was qualified to fit inverters, really quite simple for a qualified electrician, most will have covered in when they are updating their Part P. If the electrician does not under stand it, find another one. 28 minutes ago, PeterW said: only thing between you and the grid is a 100A supply fuse that will blow long after you’ve become a crisp. And it can draw a lot more current than that for a second or two before it blows. So let us say it draws 300 A at 230V for 2 seconds, that is the same as a 14 tonne weight resting on your body. Link to comment Share on other sites More sharing options...
SuperJohnG Posted November 3, 2020 Share Posted November 3, 2020 24 minutes ago, SteamyTea said: So let us say it draws 300 A at 230V for 2 seconds, that is the same as a 14 tonne weight resting on your body I'm genuinely interested in how you did this calculation/ know this. 1 Link to comment Share on other sites More sharing options...
SteamyTea Posted November 3, 2020 Share Posted November 3, 2020 (edited) 18 minutes ago, SuperJohnG said: I'm genuinely interested in how you did this calculation/ know this. Amps [A] times Volts [V] equals watts [W] A watt is a joule [J] per second. A joule is the unit of energy. So 300 [A] x 230 [V] = 69,000 [W] I said that it would run for 2 seconds 69,000 [W] x 2 = 138,000 [Ws or J] As a joule is the the force [mass x acceleration] to move 1 kg 1 metre, I used the force of gravity, 9.81 m.s2 so (and I think I did this step right, but starting to doubt myself now) 138,000 [J] / 9.81 [m.s2] = 14,067 kg. Edited November 3, 2020 by SteamyTea 1 Link to comment Share on other sites More sharing options...
NotJustin Posted November 3, 2020 Author Share Posted November 3, 2020 Anyway, like I say, I will get my electrician to do the job. But I actually do want to know how it fits into the house wiring for my own reference and interest. Link to comment Share on other sites More sharing options...
SuperJohnG Posted November 4, 2020 Share Posted November 4, 2020 2 hours ago, SteamyTea said: Amps [A] times Volts [V] equals watts [W] A watt is a joule [J] per second. A joule is the unit of energy. So 300 [A] x 230 [V] = 69,000 [W] I said that it would run for 2 seconds 69,000 [W] x 2 = 138,000 [Ws or J] As a joule is the the force [mass x acceleration] to move 1 kg 1 metre, I used the force of gravity, 9.81 m.s2 so (and I think I did this step right, but starting to doubt myself now) 138,000 [J] / 9.81 [m.s2] = 14,067 kg. Looks not bad to me...if I jave a spare 5 mins tomorrow I may just run it through mathcad. Its definitely a good analogy ? 1 Link to comment Share on other sites More sharing options...
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