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ASHP Energy Comparison


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Morning!

I had Aira come out yesterday to discuss putting a ASHP in, but I’m wondering if anyone can help me. 
I know that I used 18500kw/h of gas heating the house in 2023, so considering they suggested an 8kw heat pump, is there anyway of making a rough calculation on how much electricity it would use over a year? I can’t decide if I’m trying to calculate something that’s impossible to know, or if I’m missing a very simple calculation? Any guidance would be welcome! Thanks! 

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Welcome

 

While it depends on many other things i.e. how well set up, you can use the Seasonal Coefficient of Performance (sCoP) number to get a very rough idea.

But always remember that running a low temperature heating system is not like running a high temperature combustion heating system.

38 minutes ago, jimboflint19 said:

18500kw/h

Some other will laugh at this, but it is kWh, a measure of energy.  Not kw/h which is a nonsense unit.

 

To satisfy that 18500 kWh of energy, an 8 kW heat pump would be running for roughly 2300 hours/year (but only at full power, which it will not).  A lot of that will depend on how well your original boiler was working though.  If the efficiency was, in real life, only 70%, then you only need 13,00 kWh.

Edited by SteamyTea
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Similar gas numbers to us… two heat loss calcs came up within 200w of each other at ~7kW at -4. I fitted a 9kW unit.

 

Hard to say what the running costs are , but they’re no more than we spent on gas and the house is warmer, and has been extended.

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8 minutes ago, SteamyTea said:

Some other will laugh at this, but it is kWh, a measure of energy.  Not kw/h which is a nonsense unit.

@jimboflint19 Steamy is one of our most diligent sources of support in energy matters, indeed almost anything involving algebra, and as he will point out, I fell over this last week - and I should know better, if it is a unit named after a person then it is capatalised when used as a unit - so watts (not capitalised in a sentence unless it starts the sentence), because it is named after James Watt, otherwise it is generally not. Hence 24kWh  = Twenty four kilowatt hours. More here: https://www.nist.gov/pml/owm/writing-si-metric-system-units#:~:text=NOT 250 mms.-,Capitalization,modifier "Celsius" is capitalized. 

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3 hours ago, jimboflint19 said:

I know that I used 18500kw/h of gas heating the house in 2023, so considering they suggested an 8kw heat pump, is there anyway of making a rough calculation on how much electricity it would use over a year?

 

3 hours ago, Gary68 said:

For a rough estimates divide by 2900 so yours would be 6.3kw so your looking for a 7 or 8kw heat pump 

 

Depends quite a lot on your emitter setup. If you have (or fit) rads suitable for a 45C flow temp then from this table a 5kw Arotherm plus would do the job down to -2 OAT (southern England). Further north you would defo need the 7kW unit.

 

With a SCoP of 3.77 your 18500 kWh would require 4907 kWh of electricity to generate, which is what you originally asked, multiplied as @SteamyTea says by maybe 70% to account for the (in)efficiency of the boiler. Depending on yr HW usage (which I assume is included in the 18500) you may also need to make a correction for the fact that producing HW will be at a lower CoP, I do not know if this is included in the SCoP formula.

 

The 7kW unit has a higher SCoP so would use less, the downside would be more cycling in warmer weather, unlike a gas boiler they only modulate down to about 50% rated output, then they cycle.

 

image.png.4a5418237f5b5b2214885961cc55374e.png

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aroTHerm seem to have a strange way of sizing their units, I generally see them specked to the standard 7C/35C, air/water, the output then falls at lower air temps or/and higher water temps.

I wonder what standard, air/water, are they using?.

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Yes, rated more generously than many other mfrs. Hence I have been quoted for a 12kW Vaillant unit in place of a 15kW Stiebel Eltron.

 

Full performance tables (in Czech) are here starting at p34.

 

Extract for 5kW unit at 40 - 45C flow temp (modulation is better than I thought):

 

image.png.7401f04ebbeffdf5d03da2f29efd4d98.png

Edited by sharpener
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