pulhamdown Posted April 30, 2017 Share Posted April 30, 2017 So, is it possible to establish what the ACH @50pa is for my house from the air permeability figure of 1.42 m3(hm2). I understand that you cannot just apply a conversion ratio to get the answer, but beyond that I'm lost. Colin. Link to comment Share on other sites More sharing options...
Jeremy Harris Posted April 30, 2017 Share Posted April 30, 2017 10 minutes ago, pulhamdown said: So, is it possible to establish what the ACH @50pa is for my house from the air permeability figure of 1.42 m3(hm2). I understand that you cannot just apply a conversion ratio to get the answer, but beyond that I'm lost. Colin. If you have the actual air leakage test figure from the air test report, in m³/hr, then you can use that, together with the calculated internal volume of the house, to derive the ACH. Link to comment Share on other sites More sharing options...
pulhamdown Posted May 1, 2017 Share Posted May 1, 2017 19 hours ago, JSHarris said: If you have the actual air leakage test figure from the air test report, in m³/hr, then you can use that, together with the calculated internal volume of the house, to derive the ACH. I'm sure you can. But how? Link to comment Share on other sites More sharing options...
Jeremy Harris Posted May 1, 2017 Share Posted May 1, 2017 (edited) Just divide the measured air leakage rate in m³/hr by the volume of the house, in m³, and you should get the ACH figure. For example, our house measured air leakage rate at 50 Pa was 199m³/hr, and the house internal volume is 462m³. 199m³/hr divided by 462m³ = 0.43 Air Changes per Hour (ACH). Edited May 1, 2017 by JSHarris typo Link to comment Share on other sites More sharing options...
pulhamdown Posted May 1, 2017 Share Posted May 1, 2017 (edited) Brilliant. Thanks very much. Colin Edited May 1, 2017 by pulhamdown Typo Link to comment Share on other sites More sharing options...
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