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Saturday night nonsense


Tennentslager

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I think it's 042 as well.

  1. Nothing is correct in 738, one is correct but wrongly placed in 780 - therefore the first or second digit is zero.
  2. 206 has two digits correct but wrongly placed. We already know that the first or second digit is zero, so the first digit must be zero. One of 2 or 6 makes up one of the remaining digits, with the other not being present.
  3. 682 has one digit correct and correctly placed. Since the first digit must be a zero, the correct digit must be a 2 as the third digit.
  4. 614 has one digit correct but wrongly placed. The missing digit must be a 6 or a 4, and we know from (2) that there is no 6 present.
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  • 3 months later...
23 minutes ago, Tennentslager said:

Naw

Got it. A bit sneaky

 

3 pairs of shoes = 30, so one pair of shoes =10

 

1 pair of shoes plus 2 men = 20. We know pair of shoes = 10 so 2 men = 10 so 1 man = 5

 

man (5) plus 2 (pairs of) whistles = 13 so 2 (pairs of) whistles = 8 therefore 1 (pair of) whistles = 4

 

So the final sum single shoe (5) plus man (5) plus single whistle (2) = 12

 

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39 minutes ago, ProDave said:

Got it. A bit sneaky

 

3 pairs of shoes = 30, so one pair of shoes =10

 

1 pair of shoes plus 2 men = 20. We know pair of shoes = 10 so 2 men = 10 so 1 man = 5

 

man (5) plus 2 (pairs of) whistles = 13 so 2 (pairs of) whistles = 8 therefore 1 (pair of) whistles = 4

 

So the final sum single shoe (5) plus man (5) plus single whistle (2) = 12

 

Nope there's a X in the last line...but still wrong

Edited by Tennentslager
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It's a bit more complicated. The first ones are man plus whistle and the last one is man (no whistle)  Which means my values for man and whistle are wrong, and becomes a simultaneous equation to solve to get those.

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